Archival storage

[woodelf]

Patrick Finnegan wrote:

>John Foust declared on Tuesday 11 October 2005 07:17 pm:
>  
>
>>At 05:55 PM 10/11/2005, Patrick Finnegan wrote:
>>    
>>
>>>At 700MB/cd, it'd be about 12 reams per CD, not 92.  92 reams would
>>>get you about 5.4GB, which is more than a (single-sided, single
>>>layer) DVD-R holds.
>>>      
>>>
>>My math:
>>
>>472,500 bits per page
>>945,000 bits per double-sided page
>>118,125 bytes per double-sided page
>>681,574,400 bytes per 650 M CD
>>5,452,595,200 bits per CD
>>    
>>
>
>  
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>>46,160 pages
>>92 reams
>>59,062,500 bytes per ream
>>    
>>
>              ^^^
>That's bytes per ream, not bits per ream.
>
>681MByte/CD / 59MByte/ream = 11.5 reams/CD
>
>
>Pat
>  
>
I was looking for Fortran IV programs and got reading on the History of 
FORTRAN.
In 1957 they could not punch out the 2,000 binary cards of FORTRAN II 
and had to go tape instead.
Now that is about 72*12 bits per card ...  you work out the math.